MathematicsMedium94×since 2002Q2873The area of the region in the first quadrant inside the circle x2+y2=8x^2+y^2=8x2+y2=8 and outside the parabola y2=2xy^2=2 xy2=2x is equal to :Aπ2−13\frac{\pi}{2}-\frac{1}{3}2π−31Bπ−13\pi-\frac{1}{3}π−31Cπ−23\pi-\frac{2}{3}π−32Dπ2−23\frac{\pi}{2}-\frac{2}{3}2π−32Check answerSkip