The area enclosed by the curves … and …, above the line … is:

Option B. According to NTA, the required region … which is shaded in crossed lines and comes out to be

Area Under the Curves

JEE Main 2022 · 28 Jul, Evening shift · Q2850

MathematicsHard94×since 2002Q2850

The area enclosed by the curves

y=\log _{e}\left(x+\mathrm{e}^{2}\right), x=\log _{e}\left(\frac{2}{y}\right)

and

x=\log _{\mathrm{e}} 2

, above the line

y=1

is:

JEE Main 2022 · 28 Jul, Evening shift · Q2850

MathematicsHard94×since 2002Q2850

The area enclosed by the curves

y=\log _{e}\left(x+\mathrm{e}^{2}\right), x=\log _{e}\left(\frac{2}{y}\right)

and

x=\log _{\mathrm{e}} 2

, above the line

y=1

is: