MathematicsEasy19×since 2002Q5041The angles A, B and C of a triangle ABC are in A.P. and a : b = 1 : 3\sqrt 33. If c = 4 cm, then the area (in sq. cm) of this triangle is :A23\sqrt 33B43\sqrt 33C43{4 \over {\sqrt 3 }}34D23{2 \over {\sqrt 3 }}32Check answerSkip