PhysicsMedium202×since 2002Q8385The angle between vector Q⃗\vec{Q}Q and the resultant of (2Q⃗+2P⃗)(2 \vec{Q}+2 \vec{P})(2Q+2P) and (2Q⃗−2P⃗)(2 \vec{Q}-2 \vec{P})(2Q−2P) is :Atan−1(P/Q)\tan ^{-1}(\mathrm{P} / \mathrm{Q})tan−1(P/Q)B0∘^\circ∘Ctan−1(2Q⃗−2P⃗)2Q⃗+2P⃗\tan ^{-1} \frac{(2 \vec{Q}-2 \vec{P})}{2 \vec{Q}+2 \vec{P}}tan−12Q+2P(2Q−2P)Dtan−1(2Q/P)\tan ^{-1}(2 Q / \mathrm{P})tan−1(2Q/P)Check answerSkip