Inverse Trigonometric Functions

JEE Main 2022 · 26 Jul, Morning shift · Q4111

MathematicsMedium66×since 2002Q4111

\tan \left(2 \tan ^{-1} \frac{1}{5}+\sec ^{-1} \frac{\sqrt{5}}{2}+2 \tan ^{-1} \frac{1}{8}\right)

is equal to :

JEE Main 2022 · 26 Jul, Morning shift · Q4111

MathematicsMedium66×since 2002Q4111

\tan \left(2 \tan ^{-1} \frac{1}{5}+\sec ^{-1} \frac{\sqrt{5}}{2}+2 \tan ^{-1} \frac{1}{8}\right)

is equal to :

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