MathematicsMedium210×since 2002Q3349Statement-1 : The value of the integral ∫π/6π/3dx1+tan x\int\limits_{\pi /6}^{\pi /3} {{{dx} \over {1 + \sqrt {\tan \,x} }}}π/6∫π/31+tanxdx is equal to π/6\pi /6π/6 Statement-2 : ∫abf(x)dx=∫abf(a+b−x)dx.\int\limits_a^b {f\left( x \right)} dx = \int\limits_a^b {f\left( {a + b - x} \right)} dx.a∫bf(x)dx=a∫bf(a+b−x)dx.AStatement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.BStatement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.CStatement- 1 is true; Statement-2 is False.DStatement-1 is false; Statement-2 is true.Check answerSkip