MathematicsMedium38×since 2002Q3577Solution of the differential equation ydx+(x+x2y)dy=0ydx + \left( {x + {x^2}y} \right)dy = 0ydx+(x+x2y)dy=0 isAlogloglog y=Cxy=Cxy=CxB−1xy+logy=C- {1 \over {xy}} + \log y = C−xy1+logy=CC1xy+logy=C{1 \over {xy}} + \log y = Cxy1+logy=CD−1xy=C- {1 \over {xy}} = C−xy1=CCheck answerSkip