MathematicsMedium38×since 2002Q3579Solution of the differential equation cosx dy=y(sinx−y)dx, 0<x<π2\cos x\,dy = y\left( {\sin x - y} \right)dx,\,\,0 < x <{\pi \over 2}cosxdy=y(sinx−y)dx,0<x<2π is :Aysecx=tanx+cy\sec x = \tan x + cysecx=tanx+cBytanx=secx+cy\tan x = \sec x + cytanx=secx+cCtanx=(secx+c)y\tan x = \left( {\sec x + c} \right)ytanx=(secx+c)yDsecx=(tanx+c)y\sec x = \left( {\tan x + c} \right)ysecx=(tanx+c)yCheck answerSkip