PhysicsMedium148×since 2002Q8037Pressure inside a soap bubble is greater than the pressure outside by an amount : (given : R=\mathrm{R}=R= Radius of bubble, S=\mathrm{S}=S= Surface tension of bubble)ASR\frac{S}{R}RSB4 SR\frac{4 \mathrm{~S}}{\mathrm{R}}R4 SC4RS\frac{4 \mathrm{R}}{\mathrm{S}}S4RD2SR\frac{2 S}{R}R2SCheck answerSkip