PhysicsEasy100×since 2002Q8166Motion of a particle in x-y plane is described by a set of following equations x=4sin(π2−ωt) mx = 4\sin \left( {{\pi \over 2} - \omega t} \right)\,mx=4sin(2π−ωt)m and y=4sin(ωt) my = 4\sin (\omega t)\,my=4sin(ωt)m. The path of the particle will be :AcircularBhelicalCparabolicDellipticalCheck answerSkip