MathematicsMedium179×since 2002Q4264limx→π2[1−tan(x2)][1−sinx][1+tan(x2)][π−2x]3\mathop {\lim }\limits_{x \to {\pi \over 2}} {{\left[ {1 - \tan \left( {{x \over 2}} \right)} \right]\left[ {1 - \sin x} \right]} \over {\left[ {1 + \tan \left( {{x \over 2}} \right)} \right]{{\left[ {\pi - 2x} \right]}^3}}}x→2πlim[1+tan(2x)][π−2x]3[1−tan(2x)][1−sinx] isA∞\infty∞B18{1 \over 8}81C0D132{1 \over 32}321Check answerSkip