MathematicsMedium179×since 2002Q4275limx→1−π−2sin−1x1−x\mathop {\lim }\limits_{x \to {1^ - }} {{\sqrt \pi - \sqrt {2{{\sin }^{ - 1}}x} } \over {\sqrt {1 - x} }}x→1−lim1−xπ−2sin−1x is equal to :A2π\sqrt {{2 \over \pi }}π2B12π{1 \over {\sqrt {2\pi } }}2π1Cπ2\sqrt {{\pi \over 2}}2πDπ\sqrt \piπCheck answerSkip