MathematicsMedium179×since 2002Q4291limx→12sin(cos−1x)−x1−tan(cos−1x)\mathop {\lim }\limits_{x \to {1 \over {\sqrt 2 }}} {{\sin ({{\cos }^{ - 1}}x) - x} \over {1 - \tan ({{\cos }^{ - 1}}x)}}x→21lim1−tan(cos−1x)sin(cos−1x)−x is equal to :A2\sqrt 22B−2- \sqrt 2−2C12{1 \over {\sqrt 2 }}21D−12- {1 \over {\sqrt 2 }}−21Check answerSkip