MathematicsEasy179×since 2002Q4287limx→0sin2(πcos4x)x4\mathop {\lim }\limits_{x \to 0} {{{{\sin }^2}\left( {\pi {{\cos }^4}x} \right)} \over {{x^4}}}x→0limx4sin2(πcos4x) is equal to :Aπ2{\pi ^2}π2B2π22{\pi ^2}2π2C4π24{\pi ^2}4π2D4π4\pi4πCheck answerSkip