MathematicsEasy210×since 2002Q3309limx→0∫0x2(sint)dtx3\mathop {\lim }\limits_{x \to 0} {{\int\limits_0^{{x^2}} {\left( {\sin \sqrt t } \right)dt} } \over {{x^3}}}x→0limx30∫x2(sint)dt is equal to :A115{1 \over {15}}151B0C23{2 \over 3}32D32{3 \over 2}23Check answerSkip