MathematicsMedium210×since 2002Q3282limn→∞[1n2sec21n2+2n2sec24n2....+1nsec21]\mathop {\lim }\limits_{n \to \infty } \left[ {{1 \over {{n^2}}}{{\sec }^2}{1 \over {{n^2}}} + {2 \over {{n^2}}}{{\sec }^2}{4 \over {{n^2}}}.... + {1 \over n}{{\sec }^2}1} \right]n→∞lim[n21sec2n21+n22sec2n24....+n1sec21] equalsA12sec1{1 \over 2}\sec 121sec1B12{1 \over 2}21cosec 1Ctan 1D12{1 \over 2}21tan 1Check answerSkip