MathematicsMedium179×since 2002Q4294limx→π482−(cosx+sinx)72−2sin2x\lim\limits_{x \rightarrow \frac{\pi}{4}} \frac{8 \sqrt{2}-(\cos x+\sin x)^{7}}{\sqrt{2}-\sqrt{2} \sin 2 x}x→4πlim2−2sin2x82−(cosx+sinx)7 is equal toA14B7C142\sqrt22D72\sqrt22Check answerSkip