MathematicsMedium38×since 2002Q3532Let y = y(x) satisfies the equation dydx−∣A∣=0{{dy} \over {dx}} - |A| = 0dxdy−∣A∣=0, for all x > 0, where A = \left[ {\matrix{ y & {\sin x} & 1 \cr 0 & { - 1} & 1 \cr 2 & 0 & {{1 \over x}} \cr } } \right]. If y(π)=π+2y(\pi ) = \pi + 2y(π)=π+2, then the value of y(π2)y\left( {{\pi \over 2}} \right)y(2π) is :Aπ2+4π{\pi \over 2} + {4 \over \pi }2π+π4Bπ2−1π{\pi \over 2} - {1 \over \pi }2π−π1C3π2−1π{{3\pi } \over 2} - {1 \over \pi }23π−π1Dπ2−4π{\pi \over 2} - {4 \over \pi }2π−π4Check answerSkip