MathematicsEasy38×since 2002Q3517Let y = y(x) be the solution of the differential equation, xdydx{{dy} \over {dx}}dxdy + y = x log_e x, (x > 1). If 2y(2) = log_e 4 −-− 1, then y(e) is equal to :A−e2- {e \over 2}−2eB−e22- {{{e^2}} \over 2}−2e2Ce24{{{e^2}} \over 4}4e2De4{e \over 4}4eCheck answerSkip