Let y = y(x) be the solution of the differential equation, … such that y(0) = 0. If … = … , then the value of 'a' is :

Differential Equations

JEE Main 2019 · 8 Apr, Morning shift · Q3592

MathematicsMedium38×since 2002Q3592

Let y = y(x) be the solution of the differential equation,

{({x^2} + 1)^2}{{dy} \over {dx}} + 2x({x^2} + 1)y = 1

such that y(0) = 0. If

\sqrt ay(1)

\pi \over 32

, then the value of 'a' is :

JEE Main 2019 · 8 Apr, Morning shift · Q3592

MathematicsMedium38×since 2002Q3592

Let y = y(x) be the solution of the differential equation,

{({x^2} + 1)^2}{{dy} \over {dx}} + 2x({x^2} + 1)y = 1

such that y(0) = 0. If

\sqrt ay(1)

\pi \over 32

, then the value of 'a' is :