MathematicsMedium38×since 2002Q3524Let y = y(x) be the solution of the differential equation, 2+sinxy+1.dydx=−cosx{{2 + \sin x} \over {y + 1}}.{{dy} \over {dx}} = - \cos xy+12+sinx.dxdy=−cosx, y > 0,y(0) = 1. If y(π\piπ) = a and dydx{{dy} \over {dx}}dxdy at x = π\piπ is b, then the ordered pair (a, b) is equal to :A(2, 1)B(2,32)\left( {2,{3 \over 2}} \right)(2,23)C(1, -1)D(1, 1)Check answerSkip