MathematicsMedium38×since 2002Q3613Let y = y(x) be the solution of the differential equation xdy = (y + x³ cosx)dx with y(π\piπ) = 0, then y(π2)y\left( {{\pi \over 2}} \right)y(2π) is equal to :Aπ24+π2{{{\pi ^2}} \over 4} + {\pi \over 2}4π2+2πBπ22+π4{{{\pi ^2}} \over 2} + {\pi \over 4}2π2+4πCπ22−π4{{{\pi ^2}} \over 2} - {\pi \over 4}2π2−4πDπ44−π2{{{\pi ^4}} \over 4} - {\pi \over 2}4π4−2πCheck answerSkip