MathematicsMedium38×since 2002Q3601Let y = y(x) be a solution of the differential equation, 1−x2dydx+1−y2=0\sqrt {1 - {x^2}} {{dy} \over {dx}} + \sqrt {1 - {y^2}} = 01−x2dxdy+1−y2=0, |x| < 1. If y(12)=32y\left( {{1 \over 2}} \right) = {{\sqrt 3 } \over 2}y(21)=23, then y(−12)y\left( { - {1 \over {\sqrt 2 }}} \right)y(−21) is equal to :A−32- {{\sqrt 3 } \over 2}−23BNone of thoseC12{{1 \over {\sqrt 2 }}}21D−12-{{1 \over {\sqrt 2 }}}−21Check answerSkip