Probability

JEE Main 2022 · 27 Jul, Evening shift · Q4894

MathematicsEasy75×since 2002Q4894

Let X have a binomial distribution B(n, p) such that the sum and the product of the mean and variance of X are 24 and 128 respectively. If

P(X>n-3)=\frac{k}{2^{n}}

, then k is equal to :

JEE Main 2022 · 27 Jul, Evening shift · Q4894

MathematicsEasy75×since 2002Q4894

Let X have a binomial distribution B(n, p) such that the sum and the product of the mean and variance of X are 24 and 128 respectively. If

P(X>n-3)=\frac{k}{2^{n}}

, then k is equal to :

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