MathematicsMedium202×since 2002Q5860Let a⃗=2i^+j^−k^,b⃗=((a⃗×(i^+j^))×i^)×i^\vec{a}=2 \hat{i}+\hat{j}-\hat{k}, \vec{b}=((\vec{a} \times(\hat{i}+\hat{j})) \times \hat{i}) \times \hat{i}a=2i^+j^−k^,b=((a×(i^+j^))×i^)×i^. Then the square of the projection of a⃗\vec{a}a on b⃗\vec{b}b is:A13\frac{1}{3}31B15\frac{1}{5}51C2D23\frac{2}{3}32Check answerSkip