MathematicsHard202×since 2002Q5843Let a⃗=2i^+3j^+4k^,b⃗=i^−2j^−2k^\vec{a}=2 \hat{i}+3 \hat{j}+4 \hat{k}, \vec{b}=\hat{i}-2 \hat{j}-2 \hat{k}a=2i^+3j^+4k^,b=i^−2j^−2k^ and c⃗=−i^+4j^+3k^\vec{c}=-\hat{i}+4 \hat{j}+3 \hat{k}c=−i^+4j^+3k^. If d⃗\vec{d}d is a vector perpendicular to both b⃗\vec{b}b and c⃗\vec{c}c, and a⃗⋅d⃗=18\vec{a} \cdot \vec{d}=18a⋅d=18, then ∣a⃗×d⃗∣2|\vec{a} \times \vec{d}|^{2}∣a×d∣2 is equal to :A680B720C760D640Check answerSkip