MathematicsHard249×since 2002Q2468Let two vertices of a triangle ABC be (2, 4, 6) and (0, −-−2, −-−5), and its centroid be (2, 1, −-−1). If the image of the third vertex in the plane x+2y+4z=11x+2y+4z=11x+2y+4z=11 is (α,β,γ)(\alpha,\beta,\gamma)(α,β,γ), then αβ+βγ+γα\alpha\beta+\beta\gamma+\gamma\alphaαβ+βγ+γα is equal to :A72B74C76D70Check answerSkip