MathematicsMedium178×since 2002Q5188Let three real numbers a,b,ca, b, ca,b,c be in arithmetic progression and a+1,b,c+3a+1, b, c+3a+1,b,c+3 be in geometric progression. If a>10a>10a>10 and the arithmetic mean of a,ba, ba,b and ccc is 8, then the cube of the geometric mean of a,ba, ba,b and ccc isA120B316C312D128Check answerSkip