MathematicsMedium178×since 2002Q5204Let the sum of the first n terms of a non-constant A.P., a₁, a₂, a₃, ..... be 50n+n(n−7)2A50n + {{n(n - 7)} \over 2}A50n+2n(n−7)A, where A is a constant. If d is the common difference of this A.P., then the ordered pair (d, a₅₀) is equal toA(A, 50+45A)B(50, 50+45A)C(A, 50+46A)D(50, 50+46A)Check answerSkip