Let the solution curve of the differential equation …, … be …. Then y(2) is equal to:

Differential Equations

JEE Main 2022 · 29 Jun, Morning shift · Q3619

MathematicsHard38×since 2002Q3619

Let the solution curve of the differential equation

x{{dy} \over {dx}} - y = \sqrt {{y^2} + 16{x^2}}

y(1) = 3

y = y(x)

. Then y(2) is equal to:

JEE Main 2022 · 29 Jun, Morning shift · Q3619

MathematicsHard38×since 2002Q3619

Let the solution curve of the differential equation

x{{dy} \over {dx}} - y = \sqrt {{y^2} + 16{x^2}}

y(1) = 3

y = y(x)

. Then y(2) is equal to: