MathematicsMedium128×since 2002Q5554Let the point P(α,β)P(\alpha, \beta)P(α,β) be at a unit distance from each of the two lines L1:3x−4y+12=0L_{1}: 3 x-4 y+12=0L1:3x−4y+12=0, and L2:8x+6y+11=0L_{2}: 8 x+6 y+11=0L2:8x+6y+11=0. If PPP lies below L1L_{1}L1 and above L2{ }{L_{2}}L2, then 100(α+β)100(\alpha+\beta)100(α+β) is equal to :A−-−14B42C−-−22D14Check answerSkip