MathematicsMedium244×since 2002Q4536Let the matrix A=[010001100]A=\left[\begin{array}{lll}0 & 1 & 0 \\ 0 & 0 & 1 \\ 1 & 0 & 0\end{array}\right]A=001100010 and the matrix B0=A49+2A98B_{0}=A^{49}+2 A^{98}B0=A49+2A98. If Bn=Adj(Bn−1)B_{n}=A d j\left(B_{n-1}\right)Bn=Adj(Bn−1) for all n≥1n \geq 1n≥1, then det(B4)\operatorname{det}\left(B_{4}\right)det(B4) is equal to :A3283^{28}328B3303^{30}330C3323^{32}332D3363^{36}336Check answerSkip