MathematicsEasy175×since 2002Q2676Let the function f(x)=2x3+(2p−7)x2+3(2p−9)x−6f(x) = 2{x^3} + (2p - 7){x^2} + 3(2p - 9)x - 6f(x)=2x3+(2p−7)x2+3(2p−9)x−6 have a maxima for some value of x<0x < 0x<0 and a minima for some value of x>0x > 0x>0. Then, the set of all values of p isA(−92,92)\left( { - {9 \over 2},{9 \over 2}} \right)(−29,29)B(92,∞)\left( {{9 \over 2},\infty } \right)(29,∞)C(0,92)\left( {0,{9 \over 2}} \right)(0,29)D(−∞,92)\left( { - \infty ,{9 \over 2}} \right)(−∞,29)Check answerSkip