Let the foci of the ellipse … and the hyperbola … coincide. Then the length of the latus rectum of the hyperbola is :

Hyperbola

JEE Main 2022 · 25 Jul, Evening shift · Q3974

MathematicsMedium57×since 2003Q3974

Let the foci of the ellipse

\frac{x^{2}}{16}+\frac{y^{2}}{7}=1

and the hyperbola

\frac{x^{2}}{144}-\frac{y^{2}}{\alpha}=\frac{1}{25}

coincide. Then the length of the latus rectum of the hyperbola is :

JEE Main 2022 · 25 Jul, Evening shift · Q3974

MathematicsMedium57×since 2003Q3974

Let the foci of the ellipse

\frac{x^{2}}{16}+\frac{y^{2}}{7}=1

and the hyperbola

\frac{x^{2}}{144}-\frac{y^{2}}{\alpha}=\frac{1}{25}

coincide. Then the length of the latus rectum of the hyperbola is :