MathematicsMedium128×since 2002Q5530Let the equations of two sides of a triangle be 3x −-− 2y + 6 = 0 and 4x + 5y −-− 20 = 0. If the orthocentre of this triangle is at (1, 1), then the equation of its third side is :A122y −-− 26x −-− 1675 = 0B122y + 26x + 1675 = 0C26x + 61y + 1675 = 0D26x −-− 122y −-− 1675 = 0Check answerSkip