MathematicsHard74×since 2004Q3762Let the eccentricity of the ellipse x2+a2y2=25a2{x^2} + {a^2}{y^2} = 25{a^2}x2+a2y2=25a2 be b times the eccentricity of the hyperbola x2−a2y2=5{x^2} - {a^2}{y^2} = 5x2−a2y2=5, where a is the minimum distance between the curves y = e^x and y = log_ex. Then a2+1b2{a^2} + {1 \over {{b^2}}}a2+b21 is equal to :A32{3 \over 2}23B52{5 \over 2}25C3D5Check answerSkip