MathematicsMedium244×since 2002Q4543Let the determinant of a square matrix A of order mmm be m−nm-nm−n, where mmm and nnn satisfy 4m+n=224 m+n=224m+n=22 and 17m+4n=9317 m+4 n=9317m+4n=93. If det(nadj(adj(mA)))=3a5b6c\operatorname{det}(n \operatorname{adj}(\operatorname{adj}(m A)))=3^{a} 5^{b} 6^{c}det(nadj(adj(mA)))=3a5b6c then a+b+ca+b+ca+b+c is equal to :A96B84C109D101Check answerSkip