MathematicsHard179×since 2002Q4182Let S = { t ∈R:f(x)=∣x−π∣.(e∣x∣−1)\in R:f(x) = \left| {x - \pi } \right|.\left( {{e^{\left| x \right|}} - 1} \right)∈R:f(x)=∣x−π∣.(e∣x∣−1)sin∣x∣\sin \left| x \right|sin∣x∣ is not differentiable at t}, then the set S is equal toA{0, π\piπ}Bϕ\phiϕ (an empty set)C{0}D{π\piπ}Check answerSkip