MathematicsHard202×since 2002Q5697Let PQR be a triangle. The points A, B and C are on the sides QR, RP and PQ respectively such that QAAR=RBBP=PCCQ=12{{QA} \over {AR}} = {{RB} \over {BP}} = {{PC} \over {CQ}} = {1 \over 2}ARQA=BPRB=CQPC=21. Then Area(ΔPQR)Area(ΔABC){{Area(\Delta PQR)} \over {Area(\Delta ABC)}}Area(ΔABC)Area(ΔPQR) is equal to :A52\frac{5}{2}25B4C2D3Check answerSkip