MathematicsMedium58×since 2004Q5353Let P = {θ\thetaθ : sinθ\thetaθ −-− cosθ\thetaθ = 2 cosθ\sqrt 2 \,\cos \theta2cosθ} and Q = {θ\thetaθ : sinθ\thetaθ + cosθ\thetaθ = 2 sinθ\sqrt 2 \,\sin \theta2sinθ} be two sets. ThenAP ⊂\subset⊂ Q and Q −-− P ≠\ne= ϕ\phiϕBQ ⊄\not\subset⊂ PCP ⊄\not\subset⊂ QDP = QCheck answerSkip