Let … then … … is equal to :

Limits Continuity and Differentiability

JEE Main 2016 · Session, Shift 1 · Q4269

MathematicsEasy179×since 2002Q4269

Let

p = \mathop {\lim }\limits_{x \to {0^ + }} {\left( {1 + {{\tan }^2}\sqrt x } \right)^{{1 \over {2x}}}}

then

log

p

is equal to :

JEE Main 2016 · Session, Shift 1 · Q4269

MathematicsEasy179×since 2002Q4269

Let

p = \mathop {\lim }\limits_{x \to {0^ + }} {\left( {1 + {{\tan }^2}\sqrt x } \right)^{{1 \over {2x}}}}

then

log

p

is equal to :