MathematicsHard244×since 2002Q4664Let P=[3212−1232],A=[1101]P=\left[\begin{array}{cc}\frac{\sqrt{3}}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right], A=\left[\begin{array}{ll}1 & 1 \\ 0 & 1\end{array}\right]P=[23−212123],A=[1011] and Q=PAPTQ=P A P^{T}Q=PAPT. If PTQ2007P=[abcd]P^{T} Q^{2007} P=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]PTQ2007P=[acbd], then 2a+b−3c−4d2 a+b-3 c-4 d2a+b−3c−4d equal to :A2004B2006C2007D2005Check answerSkip