MathematicsMedium57×since 2003Q3952Let P(3, 3) be a point on the hyperbola, x2a2−y2b2=1{{{x^2}} \over {{a^2}}} - {{{y^2}} \over {{b^2}}} = 1a2x2−b2y2=1. If the normal to it at P intersects the x-axis at (9, 0) and e is its eccentricity, then the ordered pair (a², e²) is equal to :A(92,2)\left( {{9 \over 2},2} \right)(29,2)B(32,2)\left( {{3 \over 2},2} \right)(23,2)C(9,3)D(92,3)\left( {{9 \over 2},3} \right)(29,3)Check answerSkip