MathematicsMedium202×since 2002Q5856Let a→=4i^−j^+k^,b→=11i^−j^+k^\overrightarrow{\mathrm{a}}=4 \hat{i}-\hat{j}+\hat{k}, \overrightarrow{\mathrm{b}}=11 \hat{i}-\hat{j}+\hat{k}a=4i^−j^+k^,b=11i^−j^+k^ and c→\overrightarrow{\mathrm{c}}c be a vector such that (a→+b→)×c→=c→×(−2a→+3b→)(\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}) \times \overrightarrow{\mathrm{c}}=\overrightarrow{\mathrm{c}} \times(-2 \overrightarrow{\mathrm{a}}+3 \overrightarrow{\mathrm{b}})(a+b)×c=c×(−2a+3b). If (2a⃗+3b⃗)⋅c⃗=1670(2 \vec{a}+3 \vec{b}) \cdot \vec{c}=1670(2a+3b)⋅c=1670, then ∣c⃗∣2|\vec{c}|^2∣c∣2 is equal to:A1600B1618C1627D1609Check answerSkip