MathematicsHard202×since 2002Q5714Let a→=j^−k^\overrightarrow a = \widehat j - \widehat ka=j−k and c→=i^−j^−k^.\overrightarrow c = \widehat i - \widehat j - \widehat k.c=i−j−k. Then the vector b→\overrightarrow bb satisfying a→×b→+c→=0→\overrightarrow a \times \overrightarrow b + \overrightarrow c = \overrightarrow 0a×b+c=0 and a→.b→=3\overrightarrow a .\overrightarrow b = 3a.b=3 :A2i^−j^+2k^2\widehat i - \widehat j + 2\widehat k2i−j+2kBi^−j^−2k^\widehat i - \widehat j - 2\widehat ki−j−2kCi^+j^−2k^\widehat i + \widehat j - 2\widehat ki+j−2kD−i^+j^−2k^-\widehat i +\widehat j - 2\widehat k−i+j−2kCheck answerSkip