MathematicsHard202×since 2002Q5801Let a→=2i^+j^−2k^\overrightarrow a = 2\widehat i + \widehat j -2 \widehat ka=2i+j−2k and b→=i^+j^\overrightarrow b = \widehat i + \widehat jb=i+j. Let c→\overrightarrow cc be a vector such that ∣c→−a→∣=3\left| {\overrightarrow c - \overrightarrow a } \right| = 3c−a=3, ∣(a→×b→)×c→∣=3\left| {\left( {\overrightarrow a \times \overrightarrow b } \right) \times \overrightarrow c } \right| = 3(a×b)×c=3 and the angle between c→\overrightarrow cc and a→×b→\overrightarrow a \times \overrightarrow ba×b is 30∘30^\circ30∘. Then a→.c→\overrightarrow a .\overrightarrow ca.c is equal to :A2B5C18{1 \over 8}81D258{{25} \over 8}825Check answerSkip