MathematicsMedium210×since 2002Q3321Let f:R→R\mathrm{f}: \mathbb{R} \rightarrow \mathbb{R}f:R→R be defined as f(x)=ae2x+bex+cxf(x)=a e^{2 x}+b e^x+c xf(x)=ae2x+bex+cx. If f(0)=−1,f′(loge2)=21f(0)=-1, f^{\prime}\left(\log _e 2\right)=21f(0)=−1,f′(loge2)=21 and ∫0loge4(f(x)−cx)dx=392\int_0^{\log _e 4}(f(x)-c x) d x=\frac{39}{2}∫0loge4(f(x)−cx)dx=239, then the value of ∣a+b+c∣|a+b+c|∣a+b+c∣ equalsA16B12C8D10Check answerSkip