MathematicsMedium244×since 2002Q4510Let A=[aij]2×2\mathrm{A}=\left[\mathrm{a}_{\mathrm{ij}}\right]_{2 \times 2}A=[aij]2×2, where aij≠0\mathrm{a}_{\mathrm{ij}} \neq 0aij=0 for all i,j\mathrm{i}, \mathrm{j}i,j and A2=I\mathrm{A}^{2}=\mathrm{I}A2=I. Let a be the sum of all diagonal elements of A\mathrm{A}A and b=∣A∣\mathrm{b}=|\mathrm{A}|b=∣A∣. Then 3a2+4b23 a^{2}+4 b^{2}3a2+4b2 is equal to :A4B3C14D7Check answerSkip