MathematicsMedium249×since 2002Q2530Let L1:r⃗=(i^−j^+2k^)+λ(i^−j^+2k^),λ∈RL_1: \vec{r}=(\hat{i}-\hat{j}+2 \hat{k})+\lambda(\hat{i}-\hat{j}+2 \hat{k}), \lambda \in \mathbb{R}L1:r=(i^−j^+2k^)+λ(i^−j^+2k^),λ∈R, L2:r⃗=(j^−k^)+μ(3i^+j^+pk^),μ∈R, and L3:r⃗=δ(ℓi^+mj^+nk^),δ∈RL_2: \vec{r}=(\hat{j}-\hat{k})+\mu(3 \hat{i}+\hat{j}+p \hat{k}), \mu \in \mathbb{R} \text {, and } L_3: \vec{r}=\delta(\ell \hat{i}+m \hat{j}+n \hat{k}), \delta \in \mathbb{R}L2:r=(j^−k^)+μ(3i^+j^+pk^),μ∈R, and L3:r=δ(ℓi^+mj^+nk^),δ∈R be three lines such that L1L_1L1 is perpendicular to L2L_2L2 and L3L_3L3 is perpendicular to both L1L_1L1 and L2L_2L2. Then, the point which lies on L3L_3L3 isA(1,7,−4)(1,7,-4)(1,7,−4)B(1,−7,4)(1,-7,4)(1,−7,4)C(−1,7,4)(-1,7,4)(−1,7,4)D(−,1−7,4)(-, 1-7,4)(−,1−7,4)Check answerSkip