MathematicsMedium64×since 2002Q2956Let K be the sum of the coefficients of the odd powers of xxx in the expansion of (1+x)99(1+x)^{99}(1+x)99. Let aaa be the middle term in the expansion of (2+12)200{\left( {2 + {1 \over {\sqrt 2 }}} \right)^{200}}(2+21)200. If 200C99Ka=2lmn{{{}^{200}{C_{99}}K} \over a} = {{{2^l}m} \over n}a200C99K=n2lm, where m and n are odd numbers, then the ordered pair (l,n)(l,\mathrm{n})(l,n) is equal toA(50, 101)B(50, 51)C(51, 101)D(51, 99)Check answerSkip